m^2x^2+m-1=0

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Solution for m^2x^2+m-1=0 equation:


Simplifying
m2x2 + m + -1 = 0

Reorder the terms:
-1 + m + m2x2 = 0

Solving
-1 + m + m2x2 = 0

Solving for variable 'm'.

Begin completing the square.  Divide all terms by
x2 the coefficient of the squared term: 

Divide each side by 'x2'.
-1x-2 + mx-2 + m2 = 0x-2

Move the constant term to the right:

Add '1' to each side of the equation.
-1x-2 + mx-2 + 1 + m2 = 1 + 0x-2

Reorder the terms:
1 + mx-2 + m2 + -1x-2 = 1 + 0x-2

Combine like terms: 1 + 0 = 1
1 + mx-2 + m2 + -1x-2 = 1

The m term is mx-2.  Take half its coefficient (0.5x-2).
Square it (0.25x-4) and add it to both sides.

Add '0.25x-4' to each side of the equation.
1 + mx-2 + m2 + 0.25x-4 + -1x-2 = 1 + 0.25x-4

Factor a perfect square on the left side:
(m + 0.5x-2)(m + 0.5x-2) = 1 + 0.25x-4

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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